(3x^2+4x+1)/(x+1)

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Solution for (3x^2+4x+1)/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(3*x^2+4*x+1)/(x+1) = 0

3*x^2+4*x+1 = 0

3*x^2+4*x+1 = 0

DELTA = 4^2-(1*3*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-4)/(2*3) or x = (-4^(1/2)-4)/(2*3)

x = -1/3 or x = -1

(x+1)*(x+1/3) = 0

x+1/3 = 0

x+1/3 = 0 // - 1/3

x = -1/3

x = -1/3

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